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Hondamartinez9
12 joules
Last Seen
November 4, 2017
User Since
January 23, 2017
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10
Name
Anthony Martinez
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Student
School
Texas State University
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Just here to learn what this brilliant man has to offer!!!!!
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I believe they are the same. The mitotic phase (M-phase) is where mitosis and cytokinesis are coupled to make two separate daughter cells. Mitosis is just the splitting of the nuclei to form two identical nuclei while cytokinesis splits the cell into two.
Posted on October 20, 2017 | score 0
Guess I just put an extra zero... Thanks Andrey the lifesaver!!!
Posted on October 7, 2017 | score 0
When I put the numbers into my calculator, I get 2.8*10^-4 not *10^-3. Just giving a heads up :)
Posted on September 16, 2017 | score 0
Hey just giving you a heads up, the bottom equation shows m2g but when you plugged your numbers in you put "10" which is m1 not m2. Also, the denominator says 10+20 instead of 10+30. This would change the answer. Still an amazing video!!!
Posted on September 15, 2017 | score 0
I understand what you mean, the equation for F(net) is equal to F(normal) - F(gravity) and you are wondering if gravity is downward(negative in this case) why would it be minus cause the forces wouldn't cancel each other out. The minus is implied, F(net)=F(normal) + F(gravity which would be negative). Hope this clears things up for future students.
Posted on August 30, 2017 | score 0
You are correct, the difference is where the substituents lie on the double bond. If the substituents lie on opposite sides (one on the right side pointing up and the other sub. on the left side pointing down) it is known as the trans isomer which is more stable due to there not being as much steric hindrance as the cis isomer (sub. both pointing up on the double bond)
Posted on July 20, 2017 | score 0
The rate determining step is always the slow step but since the slow step, in this case, is the 2nd step, then we have to take the intermediate (product of 1st step and reactant of 2nd step) into consideration. I don't believe that in all reactions, the slow step is never in equilibrium.
Posted on July 6, 2017 | score 0
To answer both of Tittoos questions and also yours lets start with the first one. When assigning charges for certain atoms based on their pka values in pH, a good rule of thumb is if the pH is lower than the pka of a particular atom, then the atom will be protonated (which doesn't always mean it will have a net positive charge) and if the pH is higher than the pka of a particular atom, then the atom will be deprotonated. What helps me remember this is when the pH is acidic or low, then it has more H+ ions. So if the pH is beLOW the pka then there are more H+ ions to protonate the atom. For the second question, it all depends on the atom whether or not it will gain a positive charge if it becomes protonated. Sulfer in cysteines case, has 6 valence electrons (electrons on its outer most shell participating in bonding) whic means it is able to have two bonds. Since the sulfer atom has two bonds (one to the H and one to the CH2 group) and 4 lone pair of electrons, if fulfills its total of 6 valence electrons making it neutral when protonated. The reason why Nitrogen has a positive charge when protonated is due to it containing 5 valence electrons which means it can only participate in 3 bonds. But since there are 4 hydrogens bonded to it, it lost an electron causing it to have that positive charge. Hope this helps future students in their journey.
Posted on June 16, 2017 | score 1
Nature tends to want things in its lower energy state and according to the graph, the amino acids A and B are at a lower energy state than the dipeptide C making the reactants more thermodynamically favorable than the products. So this reaction would not happen spontaneously so we need to input energy for this reaction to happen. The activation energy is not the same in the forward and reverse reaction. From AB to CD it is from the lowest energy state to the top of the curve while CD to AB is from a higher energy state to the top of the curve. So the forward reaction needs moe energy to occur. The reverse reaction is thermodynamically favorable due to it decreasing energy states but kinetically unfavorable because of the high activation energy it cannot get past without some outside help. I know it is a late reply but hopefully this helps another passerby struggling with the same thing. If I am incorrect on anything please do not hesitate to correct me!
Posted on May 31, 2017 | score 1